A particle is executing simple harmonic motion of amplitude 9 m. At what point the speed of the particle will be one third of its maximum speed ?

Explanation

To find the point where the speed of a particle executing simple harmonic motion (SHM) is one third of its maximum speed, we can follow these steps:

### Step 1: Identify the maximum speed in SHM
The maximum speed \( V_{\text{max}} \) of a particle in SHM is given by the formula:
\[ V_{\text{max}} = A \cdot \omega \]
where \( A \) is the amplitude and \( \omega \) is the angular frequency.
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