On suspending a heavy block of 2 kg from a massless spring, an extension of 5 cm is produced in the spring. If the block is further pulled down by 10 cm and then released then find the kinetic energy of oscillation of the spring.

Explanation

To solve the problem step by step, we will follow the principles of mechanics and the properties of springs.

### Step 1: Determine the Spring Constant (k)

When the 2 kg block is suspended from the spring, it causes an extension of 5 cm (0.05 m). At equilibrium, the force exerted by the spring equals the weight of the block.

- Weight of the block (W) = m * g = 2 kg * 10 m/s² = 20 N
- Spring force (F_spring) = k * x = k * 0.05 m
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