A body of mass 0.5 kg is suspended by a weightless spring of force constant 500 `Nm^(-1)`. Another body of mass 0.1 kg moving vertically upwards with velocity of 5 `ms^(-1)` hits the suspended body and gets embeded into the suspended body. What will be the frequency of oscillation ?

Explanation

To find the frequency of oscillation after the two bodies collide and embed into each other, we can follow these steps:

### Step 1: Determine the effective mass after collision
The effective mass \( m_{\text{effective}} \) is the sum of the mass of the suspended body and the mass of the body that hits it:
\[ m_{\text{effective}} = m_1 + m_2 \]
Where:
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