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0.64 g of an oxide of sulphur occupies 0...

0.64 g of an oxide of sulphur occupies 0.224 L at 2 bar and `273^(@)C`. Identify the compound. Also find out the mass of one molecule of the gas.

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To solve the problem of identifying the oxide of sulfur and finding the mass of one molecule of the gas, we can follow these steps: ### Step 1: Use the Ideal Gas Law The ideal gas law is given by the equation: \[ PV = nRT \] Where: - \( P \) = pressure (in bar) - \( V \) = volume (in liters) ...
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