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A mixture of H(2) and N(2) weighing 0.11...

A mixture of `H_(2) and N_(2)` weighing 0.116 g is collected over water at `50^(@)C` and occupies a volume of 275 mL when the total pressure is 1.0 atm. Calculate the precentage of `H_(2) and N_(2)` present. Calculated the vapour pressure of water at `50^(@)C` is 92.5 torr.

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AI Generated Solution

To solve the problem of determining the percentage of hydrogen (H₂) and nitrogen (N₂) in a gas mixture collected over water, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Data:** - Mass of the gas mixture (H₂ + N₂) = 0.116 g - Volume of gas collected = 275 mL = 0.275 L (conversion from mL to L) - Total pressure (P_total) = 1.0 atm = 760 torr ...
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