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The cirtical constant for water are 374^...

The cirtical constant for water are `374^(@)C` 218 atm and 0.0566 liter `mo1^(-1)` Calculate a,b and `R` .

Text Solution

Verified by Experts

`p_(c)=(a)/(27b^(2))`
`V_(c )=3b or b=(V_(c))/(3)`
`=(0.0566)/(3)=0.0189`
`"Now "p_(c)=(a)/(27b^(2))`
`"or "a=p_(c)xx27b^(2)=218xx27xx(0.0189)^(2)`
`=2.102`
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