The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are:

Options

A. `P_(A)= 2P_(B)`
B. `P_(A)= 3P_(B)`
C. `3P_(A)= 2P_(B)`
D. `2P_(A)= 3P_(B)`

Answer

D

Explanation

`V_(A)=2V_(B)`
Compressibility factor, `Z_(A)=3Z_(B)`
`or (p_(A)V_(A))/(n_(A)RT_(A))=(3p_(B)V_(B))/(n_(B)RT_(B))`
For equal number of moles, `n_(A)=n_(B)` and same temperature `T_(A)=T_(B)`
`p_(A)V_(1)=3p_(B)" "V_(A)//2`
`"or "2p_(A)=3p_(B)`