0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume `10 m^(3)` at 1000K. Given R is the gas constant in `jk^(-1)` ,x is :

Options

A. `(2R)/(4+R)`
B. `(2R)/(4-R)`
C. `(4-R)/(2R)`
D. `(4+R)/(2R)`

Answer

C

Explanation

`"Total moles "(n_(T))=(0.5+x)`
`pV=nRT`
`200xx10=(0.5+x)xxRxx1000`
`2=(0.5+x)R`
`(2)/(R )=(1)/(2)+x`
`(2)/(R )-(1)/(2)=x or (4-R)/(2R)=x`
`therefore" "x=(4-R)/(2R)`