Home
Class 11
CHEMISTRY
Two gases X (mol. wt. M(X)) and Y (mol. ...

Two gases X `(mol. wt. M_(X))` and Y `(mol. wt. M_(Y) , M_(Y) gt M_(X))` are at the same temperature T in two different containers. Their root mean square velocities are `C_(X) and C_(Y)` respectively. If the. average kinetic energies per molecule of two gases X and Y are `E_(X) and E_(Y)` respectively, then which of the following relation (s) is (are) true ?

A

`E_(x) gt E_(y)`

B

`C_(x) gt C_(Y)`

C

`E_(x)=E_(Y)=(3)/(2)RT`

D

`E_(x)=E_(Y)=(3)/(2)k_(B)T`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the root mean square velocities and the average kinetic energies of the two gases X and Y. ### Step-by-Step Solution: 1. **Understanding Root Mean Square Velocity**: The root mean square velocity (C) of a gas is given by the formula: \[ C = \sqrt{\frac{3RT}{M}} \] where \( R \) is the universal gas constant, \( T \) is the temperature, and \( M \) is the molar mass of the gas. 2. **Applying the Formula for Both Gases**: For gas X, the root mean square velocity \( C_X \) is: \[ C_X = \sqrt{\frac{3RT}{M_X}} \] For gas Y, the root mean square velocity \( C_Y \) is: \[ C_Y = \sqrt{\frac{3RT}{M_Y}} \] 3. **Comparing the Velocities**: Given that \( M_Y > M_X \), we can compare \( C_X \) and \( C_Y \): Since \( M_Y \) is greater than \( M_X \), it follows that: \[ C_Y < C_X \] Therefore, the root mean square velocity of gas X is greater than that of gas Y. 4. **Average Kinetic Energy per Molecule**: The average kinetic energy (E) per molecule of a gas is given by: \[ E = \frac{3}{2} k_B T \] where \( k_B \) is Boltzmann's constant. 5. **Calculating Average Kinetic Energies for Both Gases**: For both gases X and Y, since they are at the same temperature \( T \): \[ E_X = \frac{3}{2} k_B T \] \[ E_Y = \frac{3}{2} k_B T \] This means: \[ E_X = E_Y \] 6. **Conclusion**: From the above analysis, we can conclude: - \( C_X > C_Y \) (the root mean square velocity of gas X is greater than that of gas Y) - \( E_X = E_Y \) (the average kinetic energy per molecule of both gases is the same) ### Final Relations: - \( C_X > C_Y \) - \( E_X = E_Y \)
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER : GASES AND LIQUIDS

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (D. MULTIPLE CHOICE QUESTIONS)|7 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (D. MULTIPLE CHOICE QUESTIONS)(Matrix Match Type Question)|2 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (B. MULTIPLE CHOICE QUESTIONS)(JEE (ADVANCED) FOR IIT ENTRANCE)|8 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise COMPETITION FILE (INTEGER TYPE AND NUMERICAL VALUE TYPE QUESTIONS)|10 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise Unit Practice Test|13 Videos

Similar Questions

Explore conceptually related problems

E_(0) and E_(n) respectively represent the average kinetic energy of a molecule of oxygen and hydrogen. If the two gases are at the same temperature, which of the following statements is true?

The HCF and LCM of two numbers x and y is 6 and 210 respectively. If x+y=72 , which of the following relation is correct?

At a given temperature, ratio of root mean square velocities of two different gases of molecular weights M_(1) and M_(2) respectively is

5g each of two solutes X and Y ( mol. wt of X gt Y) are dissolved in 100g each of same solvent.

Two cubical boxes X and Y are made up of different materials, but they have equal mass. Surface areas of boxes X and Y are 10 m^2 and 15 m^2 respectively. If P_X and P_Y are the pressure exerted by boxes X and Y on a plane surface respectively, then

If x_(i)gt0,y_(i)gt0(i=1,2,3,......n) are the values of two variable X and Y with geometric mean P and Q respectively, then the geometric mean of (X)/(Y) is