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The E^(@) values are : Cl^(-) // Cl2=+...

The `E^(@)` values are :
`Cl^(-) // Cl_2=+1.36V`, `I^(-)//I_2=+0.53V`
`Ag^(+)//Ag=+0.79V`,`Na^(+)//Na=-2.71V`
`Li^(+)//Li=-3.04V`
Arrange the following ionic species in decreasing order of reducing strength :
`I^(-),Ag^(+),Cl^(-),Li^(+),Na^(+)`

Text Solution

Verified by Experts

The lesser the `E^(@)` value , the stronger is the reducing agent . Therefore, the decreasing order of reducing strength is :
`Li^(+) gt Na^(+) gt I^(-) gt Ag^(+) Cl^(+)` .
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