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Why is KO(2) paramagnetic ?...

Why is `KO_(2)` paramagnetic ?

Text Solution

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The superoxide ion `, O_2^(-)` may be represented as :
`[:overset(..)O overset(..)(-)overset(..)O:]^(-)`
It contains one unpaired electron and therefore , it is paramagnetic . The M.O. electronic configuration of `O_2^(-)` is :
`KK(sigma2s)^(2) ( sigma**2s)^(2)(sigma2p_z)^(2)(pi2p_x)^(2)(pi2p_y)^(2)(pi**2p_x)^(2)(pi^(**)2pi_y)^(1)`
This also shows that is has one unpaired electron and hence is paramagnetic .
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a. Which alkali metal is used as a coolent in nuclear reactor ? b. What is the oxidation state of K in KO_(2) ? c. The E^(Θ) for CI_(2)CI^(Θ) is +1.36 , for I_(2)//I^(Θ) is +0.53 , for Ag^(o+)//Ag is +0.79 , for Na^(o+)//Na is -2.71 and for Li^(o+)//Li is -3.04 . Arrange the following ionic species in decreasing order of reducing strength. I^(Θ), Ag, CI^(Θ), Li, Na d. Why is KO_(2) is paramagnetic ?

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Out of Fe^(2+) and Fe^(3+) which is more paramagnetic and why?

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