`KO_2` is diamagnetic oxide.

Explanation

To determine whether \( KO_2 \) (potassium superoxide) is a diamagnetic oxide, we need to analyze the electronic configuration of the superoxide ion \( O_2^- \) and its magnetic properties. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Composition of \( KO_2 \)
- \( KO_2 \) consists of potassium ions \( K^+ \) and superoxide ions \( O_2^- \).
- The superoxide ion \( O_2^- \) is formed by adding an extra electron to the diatomic oxygen molecule \( O_2 \).

**Hint:** Remember that the superoxide ion is crucial in determining the magnetic properties of \( KO_2 \).

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