A particle experience an acceleration `a=(4e^(-3t))m/s^(2)` along positive x-axis, where t is time in s .If the initial velocity of the particle is 2m/s along positive x-axis,the velocity of the particle when its acceleration becomes zero is?

. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

A particle moves along x-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero is

A time varying force, F=2t is acting on a particle of mass 2kg moving along x-axis. velocity of the particle is 4m//s along negative x-axis at time t=0 . Find the velocity of the particle at the end of 4s.

The acceleration - time graph for a particle moving along x - axis is shown in figure, If the initial velocity of particle is -5m//s , the velocity at t = 8 s is

A particle moves along x-axis with acceleration a=6(t-1) where t is in second. If the particle is initially at the origin and it moves along positive x-axis with v_(0)=2m//s , find the nature of motion of the particle.

The motion of a particle along a straight line is described by the equation: x=8+12t-t^(3) , where x is inmeter and t in second. (i) the initial velocity of particle is 12 m//s (ii) the retardation of particle when velocity is zero is 12 m//s^(2) (iii) when acceleration is zero, displacement is 8 m the maximum velocity of particle is 12 m//s

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

A particle moves along "x" -axis with an acceleration a=12x^(2)ms^(-2) .The particle has zero velocity at "x=(-2)m" .Find the velocity of the particle (in m/sec)as it passes through origin.

Two particles are moving along x-axis. Particle-1 is 40 m behind Particle-2. Particle-1 starts with velocity 12 m//s and acceleration 4 m//s^2 both in positive x-direction. Particle-2 starts with velocity 4 m//s and acceleration 12 m//s^2 also in positive x-direction. Find (a) the time when distance between them is minimum. (b) the minimum distacne between them.

A particle moves along the x-axis obeying the equation x=t(t-1)(t-2) , where x is in meter and t is in second a. Find the initial velocity of the particle. b. Find the initial acceleration of the particle. c. Find the time when the displacement of the particle is zero. d. Find the displacement when the velocity of the particle is zero. e. Find the acceleration of the particle when its velocity is zero.