A body of mass 4 kg collides elastically with another body of mass 2 kg at rest. If time of collision is 0.02 sec and average impulse force acted on each body is 100N, find the velocity of 4kg body before and after collision (Assuming collision takes place on a smooth horizontal surface)

Explanation

To solve the problem step by step, we will use the principles of impulse and momentum, along with the conservation of momentum and the properties of elastic collisions.

### Step 1: Understand the given data
- Mass of body 1 (M1) = 4 kg
- Mass of body 2 (M2) = 2 kg
- Initial velocity of body 1 (U1) = V0 (unknown)
- Initial velocity of body 2 (U2) = 0 m/s (at rest)
- Average impulse force (F) = 100 N
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