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A bomb of mass m is thrown with velocity...

A bomb of mass m is thrown with velocity v. It explodes and breaks into two fragments. One fragment of mass m', immediately after the explosion, comes to rest. The speed of the other fragment will be

A

`(mv)/(m-m')`

B

`(mv)/(m')`

C

v

D

`(mv)/(m+m')`

Text Solution

Verified by Experts

`mv=m.(0)+(m-m.)v rArr v = (mv)/(m-m.)`
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