A massive ball moving with speed v collieds with a tiny ball which is intially at rest having a mass very much smaller than the mass of the first ball. The collision is elastic, then immediately after the impact, the second ball will move with a speed approximately equal to :-

Options

A. v
B. 2v
C. v/2
D. `oo`

Explanation

Using the formula,
`v_(2)=(2m_(1))/(m_(1)+m_(2))u_(1) " " (because u_(2)=0)`
When `m_(2)lt lt m_(1)`
`rArr (m_(2))/(m_(1))~= 0 rArr v_(2)=2u_(1)`, putting `u_(1)=v`, we obtain `u_(2)=2v`.