A ball of mass 50 gm is dropped from a height h = 10 m. It rebounds losing 75 percent of its total mechanical energy. If it remains in contact with the ground for `Delta t = 0.01` sec, find the impulse of the impact force.

Explanation

To solve the problem step-by-step, we will follow the principles of energy conservation and impulse-momentum theorem.

### Step 1: Calculate the initial velocity just before impact
The ball is dropped from a height \( h = 10 \, \text{m} \). We can find the velocity just before impact using the formula for gravitational potential energy converted to kinetic energy.

\[ v_0 = \sqrt{2gh} \]
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