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An object is projected vertically upward...

An object is projected vertically upwards. It explodes at the topmost point of its trajectory into three identical fragments. One of the fragments comes straight down in time `t_(1)` while the other two lands at a time `t_(2)` after explosion. Height at which the explosion occurred is equal to

A

`(g t_(1)t_(2)(t_(2)+3t_(1)))/(2(t_(1)+t_(2)))`

B

`(g t_(1)t_(2)^(2))/(2t_(3))`

C

`(g t_(1)t_(2)(t_(1)+2t_(2)))/(2(2t_(1)+t_(2)))`

D

`(g t_(1)t_(2)(2t_(1)+t_(2)))/(4(t_(1)+2t_(2)))`

Text Solution

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The correct Answer is:
C
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