Two blocks of mass 2 kg and 4 kg are kept in contact with each other on a smooth horizontal surface. A horizontal force of 12 N is applied on the first block due to which they move with certain constant acceleration. Calculate the force between the blocks.
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Let a = common acceleration of blocks, R = Force between the two blocks From FBD of block 1 `F-R=m_(1)a " "...(i)` From FBD of block 2, `R=m_(2)a " " ...(ii)` `therefore ` From (i) & (ii), `F=(m_(1)+m_(2)).a` `therefore a=(F)/(m_(1)+m_(2))=(12)/(6)=2m//sec^(2)` `therefore ` Force between blocks `R=m_(2)a = (4 xx 2) N=8N`.
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