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A block of mass m = 10 kg is pulled by a...

A block of mass m = 10 kg is pulled by a force F = 100 N at an angle `theta=30^(@)` with the horizontal along a smooth horizontal surface. What is the acceleration of the block? `(g = 10m//s^(2))`

Text Solution

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The F.B.D. of the block shows the force components.
Along X-axis, let let the acceleration of the block be .a.
`rArr F cos theta= m a " " ...(1)`
`rArr a=(F cos theta)/(m) " " ...(2)`
`=(100cos30^(@))/(10)=(100sqrt(3))/(2xx10)=5sqrt(3) m//s^(2)`
`therefore ` The acceleration of the block is `5sqrt(3)m//s^(2)` directed towards right. Since `F sin theta lt mg` & the surface is rigid, the block remains in equilibrium along Y-axis.
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