A block pulley arrangement is shown in the figure. If `f_(1) and f_(2)` represents frictional force acting on the block A and B respectively then choose the correct statement. (given `g=10m//s^(2)`)

Options

A. `T_(1)=100N, T_(2)=10N`
B. `f_(1)=10N, f_(2)=450N`
C. `T_(2)=50N, T_(3)=50N`
D. `f_(1)=50N, T_(2)=50N`

Answer

C

Explanation

`f_("max")=f_(1_("max"))+f_(2_("max"))=150+450=600N`
Hence A and B have no acceleration but block C has a tendency to move down.
Hence `T_(1)=500N, f_(2)=450N, T_(2)=50N, T_(3)=50N, f_(1)=0N`