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Consider the case of two bodies of masse...

Consider the case of two bodies of masses `m_(1) and m_(2)` which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations:

(i) when `m_(1) gt m_(2)`. In this case
`a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g`
(ii) when `m_(2) gt m_(1)`. In this case
`a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g`
(iii) When `m_(1)=m_(2)=m`. In this case `a = 0, T = mg`
What is the tension in the string?

A

60N

B

75N

C

100N

D

600N

Text Solution

Verified by Experts

The correct Answer is:
B
`T=(2(10)(6))/(16)g=75N`
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