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A baseball of mass m is thrown upward wi...

A baseball of mass m is thrown upward with some initial speed. If air resistance is neglected, what is the force on the ball: (a) when it reaches half its maximum height, and (b) when it reaches its peak?

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To solve the problem, we need to analyze the forces acting on the baseball at two different points in its trajectory: when it reaches half its maximum height and when it reaches its peak. ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Baseball**: The only force acting on the baseball, when air resistance is neglected, is the gravitational force. This force can be expressed as: \[ F_g = m \cdot g ...
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Knowledge Check

  • A ball of mass m is thrown upwards with a velocity v. If air exerts an average resisting force F, the velocity with which the ball returns to the thrower is

    A
    `v sqrt((mg)/(mg+F))`
    B
    `v sqrt((F)/( mg +F))`
    C
    `v sqrt((mg -F)/( mg +F))`
    D
    `v sqrt((mg +F)/( mg ))`

  • A ball of mass m is thrown upward with a velocity upsilon . If air exerts an average resisting force F, the velocity with which the ball returns to the thrower is

    A
    `vsqrt((mg)/(mg+F))`
    B
    `vsqrt((F)/(mg+F))`
    C
    `vsqrt((mg-F)/(mg+F))`
    D
    None of these

  • An object projected upward acquires a velocity of 9.8 ms^(-1) , when it reaches half of the maximum height, The maximum height reached is :-

    A
    4.9 m
    B
    7.8 m
    C
    8.8 m
    D
    9.8 m

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