Find the accelerations of rod A and wedge B in the arrangement shown in figure if the ratio of the mass of the wedge to that of the rod equals `eta`, and the friction between all contact surfaces is negligible.

Explanation

`y=x tan alpha rArr (d^(2)y)/(dt^(2))=(d^(2)x)/(dt^(2)) tan alpha`
`a_("rod")=a_("wedge"). tan alpha " " `(constraint equation)
`mg-N cos alpha=ma_(R)" " & N sin alpha=(eta m).a_("wedge")`
`rArr mg-N cos alpha=m a_(w) tan alpha`
Solving we get,
`a_("wedge")=(g)/(tan alpha+eta cot alpha) and a_("Rod")=(g)/(1+eta cot^(2)alpha)`