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A constant force of 0.75 N is acting on ...

A constant force of 0.75 N is acting on a block of mass 0.125 kg. Its direction of action in changing according to the relation `alpha=10^(-3)t` radian. Static friction coefficient of the floor block system is `3//4`. Time after which the block starts slipping, will be : `(g=10m//s^(2))`

A

314.0 s

B

423.0 s

C

515.5 s

D

645.5 s

Text Solution

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The correct Answer is:
D
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