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A constant force of 0.75 N is acting on ...

A constant force of 0.75 N is acting on a block of mass 0.125 kg. Its direction of action in changing according to the relation `alpha=10^(-3)t` radian. Static friction coefficient of the floor block system is `3//4`. Time after which the block starts slipping, will be : `(g=10m//s^(2))`

A

314.0 s

B

423.0 s

C

515.5 s

D

645.5 s

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A block of mass 1 kg is placed on a truck which accelerates with acceleration 5ms^(-2) . The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is

    A
    5 N
    B
    6 N
    C
    5.82 N
    D
    4.6 N

  • A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )

    A
    15 N downwards
    B
    25 N upwards
    C
    20 N downwards
    D
    30 N upwards

  • The force acting on the block of mass 1 kg is given by F=5-2t . The frictional force acting on the block after time t=2 seconds will be: (mu=0.2)

    A
    `2N`
    B
    `3N`
    C
    `1N`
    D
    zero
    • FIITJEE-LAWS OF MOTION-ASSIGNMENT PROBLEMS (OBJECTIVE) (Level - 1)
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    6. On the horizontal surface of plank a block of mass 1 kg is placed (mu=...

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    8. A 7500 kg rocket is set for vertical firing. The exhaust speed is 800 ...

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    14. Given m(A) = 30 kg, m(B) = 10 kg, m(C) = 20 kg. Between a & B mu(1) = ...

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