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A homogoneous chain of length L lies on ...

A homogoneous chain of length L lies on a table. The coefficient of friction between the chain and the table is `mu`. The maximum length which can hang over the table in equilibrium is

A

`(muL)/(1+mu)`

B

`((1-mu)/(mu))L`

C

`((1-mu)/(1+mu))^(2)`

D

`((2mu)/(1+2mu))L`

Text Solution

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The correct Answer is:
A
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FIITJEE-LAWS OF MOTION-ASSIGNMENT PROBLEMS (OBJECTIVE) (Level - 1)
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