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The period of oscillation of the wooden ...

The period of oscillation of the wooden cylinder is `T_(c)` in the liquid. If the liquid accelerates up with an acceleration a time new time period of oscillation will be T say Then `(T)/(T_(0))` is equal to

A

`1 : 1`

B

`g : a`

C

`sqrt(g : (g + a))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Time period will remain same in both the cases,
Constant force will only charge its equilibrium position
`:. (T)/(T_(0)) =1s`
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