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The bob of a simple pendulum of length L...

The bob of a simple pendulum of length L is released at time t = 0 from a position of small angular displacement ` theta _ 0 ` . Its linear displacement at time t is given by :

A

`x = theta sin 2pi sqrt((L)/(g))t`

B

`x = L theta cos 2pi sqrt((g)/(L)) t`

C

`x = L theta sqrt((g)/(L)) t`

D

`x = L theta cos sqrt((g)/(L)) t`

Text Solution

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The correct Answer is:
D
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