The displacement of a particle in an SHM in one time period is

Options

A. A
B. 2A
C. 4A
D. zero

Answer

To solve the question regarding the displacement of a particle in Simple Harmonic Motion (SHM) over one time period, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding SHM**:
- In SHM, a particle oscillates back and forth around a mean position (equilibrium position). The particle moves between two extreme positions, known as the amplitude positions (let's call them A and B).

2. **Defining the Time Period**:
- The time period (T) is the time taken for the particle to complete one full cycle of motion. This means the particle moves from one extreme position (A) to the other extreme position (B) and then returns back to the starting position (A).

3. **Analyzing the Motion**:
- If we consider the motion of the particle:
- It starts at position A (one extreme), moves to position B (the other extreme), and then returns to position A.
- During this entire motion, the particle travels a distance but returns to its original position.

4. **Calculating Displacement**:
- Displacement is defined as the change in position of the particle. It is a vector quantity that considers both magnitude and direction.
- Since the particle starts at position A and ends at position A after one complete cycle, the net change in position is zero.

5. **Conclusion**:
- Therefore, the displacement of the particle in one complete time period is **zero**.

### Final Answer:
The displacement of a particle in SHM in one time period is **0**.

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