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Angle of dip delta and latitude lambda o...

Angle of dip `delta` and latitude `lambda` on earth's surface are related as

A

`tan delta = 2 tan lambda`

B

`tan delta = cot lambda`

C

`tan delta = (tan lambda)/(2)`

D

`tan delta = tan lambda`

Text Solution

Verified by Experts

The correct Answer is:
A
`B_(r) = (mu_(0))/(4pi) (2M cos theta)/(r^(3))`
`B_(theta) = (mu_(0))/(4pi) (M sin theta)/(r^(3))`
Since `theta = 90^(@) + lambda` , thus
`B_(r) = (mu_(0))/(4pi) (2M cos (90 + lambda))/(r^(3)) = - (mu_(0))/(4pi) (2M sin lambda)/(r^(3))`
`B_(theta) = (mu_(0))/(4pi) (M sin (90 + lambda))/(r^(3)) = (mu_(0))/(4pi) (M cos lambda)/(r^(3))`
`therefore tan delta = (B_(V))/(B_H) = 2 tan lambda`
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