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A magnet makes 40 oscillations per minut...

A magnet makes `40` oscillations per minute at a place having magnetic field intensity of `0.1xx10^(-5)T`. At another place, it takes 2.5 sec to complete one vibrating. The value of earth's horizontal field at that place is

A

`0.25 xx 10^(-6) T`

B

`0.36 xx 10^(-6) T`

C

`0.66 xx 10^(-8) T`

D

`1.2 xx 10^(-6) T`

Text Solution

Verified by Experts

The correct Answer is:
B
`T_(1) = (60)/(40) = 1.5 ` sec `T_(2) = 2.5` sec
`T prop sqrt((1)/(B_(H)))`
`therefore (T_(2))/(T_(1)) = sqrt((B_(H1))/(B_(H2)))`
`therefore B_(H2)
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