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A magnet of magnetic moment 20 A - m^...

A magnet of magnetic moment 20 `A - m^(2)` is freely suspended is a uniform magnetic field of strength 6 T . Work done to rotate it by `60^(@)` will be .

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To solve the problem of calculating the work done to rotate a magnet by 60 degrees in a uniform magnetic field, we can follow these steps: ### Step 1: Understand the Given Information We have: - Magnetic moment (M) = 20 A·m² - Magnetic field strength (B) = 6 T - Angle of rotation (θ) = 60° ...
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