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A square loop of side 1 m is placed in a...

A square loop of side 1 m is placed in a perpendicular magnetic field. Half of the area of the loop lies inside the magnetic field . A battery of emf 10 V and negligible intermal resistance is connected in the loop . The magnetic field changes with time according to the relation B= (0.01 -2t) tesla . The resultant emf of the circuit is

A

1 V

B

11 V

C

9 V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
C
`e_("induced ") = (dphi)/(dt) = -(d)/(dt) (BA) = -A""(dB)/(dt)`
`= (l^(2))/(2) (d(0.01-2t))/(dt)=1 ` Volt
`:.` Resultant emf `= 10 -1 =9V`
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