A straight horizontal conductor PQ of length l, and mass_ m slides down on two smooth conducting fixed parallel rails, set inclined at an angle 9 to the horizontal as shown in figure-5.30.
The top end of the bar are connected with a capacitor of capacitance C. The system is placed in a uniform magnetic field, in the direction perpendicular to the inclined plane formed by the rails as shown in figure. If the resistance of the bars and the sliding conductor are negligible calculate the acceleration of sliding conductor as a function of time ifit is released from rest at t= 0

Answer

`a=(mgsin theta)/(m+B^(2)l^(2)c)`