Two parallel long smooth conducting rails separated by a distance `l` are connected by a movable conducting connector of mass `m`. Terminals of the rails are connected by the resistor `R` and the capacitor `C` as shown in figure. A uniform magnetic field `B` perpendicular to the plane of the rail is switched on. The connector is dragged by a constant force `F`. Find the speed of the connector as a function of time if the force `F` is applied at `t = 0`. Also find the terminal velocity of the connector.

Answer

`v=(FR)/(B^(2)l^(2))[i-e^((B^(2)l^(2)1)/(R(m+B^(2)l^(2)c)))]` Terminal velocity = `(FR)/(B^(2)l^(2))`