The capacitor of capacitance C can be charged (with the help of a resistance R ) by a voltage source V, by closing switch `S_(1)` while keeping switch `S_(2)` open. The capacitor can be connected in series with an inductor 'L' by closing switch `S_(2)` and opening `S_(1)`.

If the total charge storge in the LC circuit is `Q_(0)`, then for t `ge` 0

Options

A. the charge on the capacitor is Q = `Q_(0) cos ((pi)/(2) + (t)/(sqrt(LC)))`
B. the charge on the capacitor is Q = `Q_(0) cos((pi)/(2) - (1)/(sqrt(LC)) )`
C. the charge on the capacitor is Q = LC `(d^(2)Q)/(dt^(2))`
D. the charge on the capacitro is Q = - `(1)/(sqrt(LC)) (d^(2) Q)/(dt^(2))`

Answer

C