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An air plane with 20m wing spread is flying at 250 m/s straight along south parallel to the earth surface. The earth's magnetic field has a horizontal component of `2 xx 10^(5) Wb//m^(2)` and the dip angle is `60^(@)` Calculate the induced emf between the wing tips.

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To calculate the induced EMF between the wing tips of the airplane, we will follow these steps: ### Step 1: Understand the problem The airplane is flying south with a wing span of 20 meters at a speed of 250 m/s. The horizontal component of the Earth's magnetic field is given as \( B_H = 2 \times 10^{-5} \, \text{Wb/m}^2 \) and the dip angle is \( 60^\circ \). ### Step 2: Identify the relevant formula The induced EMF (\( \mathcal{E} \)) in a moving conductor can be calculated using the formula: \[ ...
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