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An average induced emg of 0.20 V appears...

An average induced emg of 0.20 V appears in a coil when the current in it is changed from 5.0 A in one direction to 5.0 A in the opposite direction in 0.20 s. find the self inductance of the coil.

Text Solution

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As `epsilon = - L (di)/(dt)`
`(di)/(dt) = ((-5.0) - (5.0))/(0.20) = `- 50A/s
Self inductance L = - `(epsilon)/(di/dt) = - (20)/((-50)) = 4 ` mH
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