Which of the following alkane upon dichlorination can give only two products ?

Options

A. `CH_(3)-CH_(2)-CH_(3)`
B. `CH_(4)`
C. `C(CH_(3))_(4)`
D.

Answer

To determine which alkane upon dichlorination can yield only two products, we need to analyze the possible products formed by the dichlorination of each alkane. Dichlorination involves the substitution of hydrogen atoms in the alkane with chlorine atoms, and the products depend on the structure of the alkane.

### Step-by-Step Solution:

1. **Identify the Alkanes**: Let's consider the four alkanes provided in the question. For this example, let's assume they are:
- A) Butane (C4H10)
- B) Propane (C3H8)
- C) Isobutane (C4H10)
- D) Ethane (C2H6)

2. **Dichlorination Process**: Dichlorination can occur in two ways:
- Both chlorine atoms can attach to the same carbon atom.
- Chlorine atoms can attach to different carbon atoms.

3. **Analyze Each Alkane**:
- **Butane (C4H10)**:
- Possible products:
- Cl on C1 and Cl on C1 (C1Cl2C2H9)
- Cl on C1 and Cl on C2 (C1ClC2ClC2H8)
- Cl on C2 and Cl on C2 (C2Cl2C1H9)
- Cl on C2 and Cl on C3 (C2ClC3ClC1H8)
- Cl on C3 and Cl on C4 (C3ClC4ClC1H8)
- Total products: More than 2.

- **Propane (C3H8)**:
- Possible products:
- Cl on C1 and Cl on C1 (C1Cl2C2H7)
- Cl on C1 and Cl on C2 (C1ClC2ClC2H6)
- Cl on C2 and Cl on C2 (C2Cl2C1H7)
- Total products: More than 2.

- **Isobutane (C4H10)**:
- Possible products:
- Cl on C1 and Cl on C1 (C1Cl2C2H9)
- Cl on C1 and Cl on C2 (C1ClC2ClC2H8)
- Cl on C1 and Cl on C3 (C1ClC3ClC2H8)
- Cl on C2 and Cl on C2 (C2Cl2C1H9)
- Total products: More than 2.

- **Ethane (C2H6)**:
- Possible products:
- Cl on C1 and Cl on C1 (C1Cl2C1H4)
- Cl on C1 and Cl on C2 (C1ClC2ClC1H4)
- Total products: Only 2 (C1Cl2C1H4 and C1ClC2ClC1H4).

4. **Conclusion**: The alkane that gives only two products upon dichlorination is **Ethane (C2H6)**.

### Final Answer:
The alkane that upon dichlorination can give only two products is **Ethane (C2H6)**.