Identify the product in the reaction
`HC-=CH overset(K_(2)Cr_(2)O_(7)+H_(2)SO_(4))underset([O])to "Product"`

Options

A. `CH_(3)CHO`
B. `CH_(3)CH_(2)OH`
C. `CH_(3)COOH`
D. `CH_(3)OH`

Answer

To identify the product of the reaction between ethyne (HC≡CH) and the oxidizing agent potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the reaction are ethyne (HC≡CH) and the oxidizing agent potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄).

2. **Understand the Reaction Type**: This is an oxidation reaction. Potassium dichromate is a strong oxidizing agent, and it will oxidize the alkyne (ethyne) to a carboxylic acid.

3. **Write the Structure of Ethyne**: Ethyne (HC≡CH) can be represented as:
\[ \text{C}_2\text{H}_2 \quad \text{(HC≡CH)} \]

4. **Determine the Oxidation Products**: When ethyne is oxidized by K₂Cr₂O₇ in the presence of H₂SO₄, it undergoes oxidation to form acetic acid (CH₃COOH). The reaction can be summarized as:
\[ \text{HC≡CH} \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4} \text{CH}_3\text{COOH} \]

5. **Write the Balanced Reaction**: The overall balanced equation for the oxidation of ethyne can be represented as:
\[ \text{C}_2\text{H}_2 + \text{O} \rightarrow \text{CH}_3\text{COOH} \]
Here, the oxygen (O) comes from the oxidizing agent.

6. **Identify the Final Product**: The final product of the reaction is acetic acid (CH₃COOH).

7. **Select the Correct Option**: Based on the options provided (A, B, C, D), the correct answer is option C, which corresponds to CH₃COOH.

### Final Answer:
The product of the reaction is **CH₃COOH** (acetic acid), and the correct option is **C**.