In which alkane isomerization will not occur ?

Options

A. `C_(2)H_(6)`
B. `C_(4)H_(10)`
C. `C_(5)H_(10)`
D. `C_(6)H_(14)`

Answer

To determine in which alkane isomerization will not occur, we need to analyze the structure of alkanes and understand the concept of isomerization.

### Step-by-Step Solution:

1. **Understanding Isomerization**: Isomerization refers to the process where compounds with the same molecular formula can exist in different structural forms (isomers). For alkanes, this typically involves variations in the carbon chain structure (chain isomerism).

2. **Identifying Alkanes**: Alkanes are saturated hydrocarbons with the general formula CnH2n+2. The simplest alkanes are methane (C1H4), ethane (C2H6), propane (C3H8), and butane (C4H10).

3. **Analyzing Simple Alkanes**:
- **Methane (C1H4)**: Only one carbon atom; no other arrangement is possible. Thus, no isomerization can occur.
- **Ethane (C2H6)**: Two carbon atoms can only be arranged in one way. No isomerization.
- **Propane (C3H8)**: Three carbon atoms can also only be arranged in one way. No isomerization.
- **Butane (C4H10)**: Four carbon atoms can be arranged in two different ways (n-butane and isobutane). Isomerization can occur.

4. **Conclusion**: Among the alkanes mentioned, methane (C1H4), ethane (C2H6), and propane (C3H8) do not exhibit isomerization due to their limited number of carbon atoms. However, the question asks for a specific alkane where isomerization will not occur, and that is **ethane (C2H6)**, as it has the least number of carbon atoms that can form only one structure.

### Final Answer:
Isomerization will not occur in **ethane (C2H6)**.