The reaction of `CH_(3)CH=CH_(2)` with HOCl will yield

Options

A. 2-chloro-1-propanol
B. 3-chloro-2-propanol
C. 1-chloro-2-propanol
D. 1-chloro-1-propanol

Answer

To determine the product of the reaction between propene (CH3CH=CH2) and hypochlorous acid (HOCl), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Propene (CH3CH=CH2)
- Hypochlorous acid (HOCl)

### Step 2: Understand the Mechanism
In the presence of HOCl, the double bond in propene will react with the electrophilic species (the positive part of HOCl). The oxygen in HOCl has a high electron density, which means it can attract electrons from the double bond.

### Step 3: Electrophilic Attack
When the double bond attacks the positive part of HOCl, one of the carbons in the double bond will form a bond with the chlorine (Cl), and the other carbon will bear a positive charge (carbocation). This occurs because the double bond is nucleophilic and can stabilize the positive charge.

### Step 4: Nucleophilic Attack
The hydroxyl group (OH) from HOCl, which is negatively charged, will then attack the positively charged carbon. This results in the formation of an alcohol.

### Step 5: Determine the Product Structure
The product structure can be represented as follows:
- The chlorine (Cl) is attached to one carbon, and the hydroxyl group (OH) is attached to the adjacent carbon.

The resulting structure can be written as:
- CH3-CH(OH)-CH2Cl

### Step 6: Name the Product
To name the product, we need to identify the longest carbon chain and the substituents:
- The longest carbon chain has three carbons, which is propane.
- The hydroxyl group (OH) is on the second carbon, and the chlorine (Cl) is on the first carbon.

Thus, the IUPAC name of the product is:
- 1-Chloro-2-propanol

### Final Product
The final product of the reaction between propene and hypochlorous acid is:
- **1-Chloro-2-propanol**

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