Toulene `overset(K_(2)Cr_(2)O_(7))underset(H_(2)SO_(4))to` Y. Here Y is

Options

A. Benzaldehyde
B. Toulene
C. Benzoic acid
D. Ethylbenzene

Answer

To solve the question regarding the oxidation of toluene using potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is Toluene, which has the chemical formula C₇H₈. It consists of a benzene ring with a methyl group (–CH₃) attached to it.

2. **Understand the Reaction Conditions**:
- Potassium dichromate (K₂Cr₂O₇) is a strong oxidizing agent. When used in the presence of sulfuric acid (H₂SO₄), it can oxidize certain organic compounds.

3. **Determine the Type of Reaction**:
- The reaction is an oxidation reaction. In this case, the methyl group (–CH₃) attached to the benzene ring in toluene will be oxidized.

4. **Predict the Product of the Reaction**:
- The oxidation of toluene (C₇H₈) will convert the methyl group into a carboxylic acid group (–COOH).
- The product formed from this oxidation will be benzoic acid (C₇H₆O₂).

5. **Write the Final Answer**:
- Therefore, the compound Y formed from the oxidation of toluene with K₂Cr₂O₇ in the presence of H₂SO₄ is **Benzoic Acid**.

### Final Answer:
Y is **Benzoic Acid**.