In Friedel-Craft's reaction, toulene can be prepared by

Options

A. `C_(6)H_(6) + CH_(3)Cl`
B. `C_(6)H_(6) + CH_(4)`
C. `C_(6)H_(6) + CH_(2)Cl_(2)`
D. `C_(6)H_(6) + CH_(3)COCl`

Answer

To prepare toluene via Friedel-Crafts reaction, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The primary reactants for the Friedel-Crafts alkylation are benzene (C6H6) and an alkyl halide (R-X), where R represents an alkyl group and X is a halogen.

2. **Choose the Lewis Acid Catalyst**:
- A Lewis acid, such as aluminum chloride (AlCl3), is required to facilitate the reaction. The Lewis acid will help in generating the electrophile from the alkyl halide.

3. **Formation of the Electrophile**:
- When the alkyl halide (R-X) reacts with the Lewis acid (AlCl3), it generates a carbocation (R^+) or an electrophile. For example, if we use methyl chloride (CH3Cl), the reaction will produce a methyl cation (CH3^+).

4. **Electrophilic Attack on Benzene**:
- The generated electrophile (R^+) will then attack the benzene ring. This occurs at one of the carbon atoms in the benzene, resulting in the formation of a sigma complex (also known as an arenium ion).

5. **Deprotonation**:
- The sigma complex is unstable and will lose a proton (H^+) to restore the aromaticity of the benzene ring. This step results in the formation of toluene (C7H8).

6. **Final Product**:
- The final product of the reaction is toluene, which has a methyl group (CH3) attached to the benzene ring.

### Summary of the Reaction:
Benzene + Methyl chloride (CH3Cl) + AlCl3 → Toluene (C7H8) + HCl