Identify Z in the sequence of reaaction
`CH_(3)-CH_(2)-CH=CH_(2) overset(HBr)underset(H_(2)O_(2)//hv)to Z`

Options

A. `CH_(3)-CH_(2)-underset(Br)underset(|)CH-CH_(3)`
B. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-Br`
C. `CH_(3)-underset(Br)underset(|)CH-CH=CH_(3)`
D. None of these

Answer

To identify the product Z in the given reaction sequence, we will follow these steps:

### Step 1: Understand the Reaction Conditions
The reaction involves the addition of HBr in the presence of hydrogen peroxide (H₂O₂) and light (hv). The presence of H₂O₂ and light indicates that the reaction will proceed via a free radical mechanism rather than through the typical electrophilic addition.

### Step 2: Identify the Starting Material
The starting material is 1-butene (CH₃-CH₂-CH=CH₂). This compound has a double bond between the second and third carbon atoms.

### Step 3: Initiation of Free Radical Reaction
In the presence of light and H₂O₂, HBr will dissociate into H• (hydrogen radical) and Br• (bromine radical). The double bond in 1-butene will also break, leading to the formation of free radicals.

### Step 4: Formation of Radicals
When the double bond breaks, two radicals can be formed:
1. A primary radical at the terminal carbon (C1)
2. A secondary radical at the second carbon (C2)

### Step 5: Stability of Radicals
The stability of radicals is crucial in determining the product. Secondary radicals are more stable than primary radicals due to hyperconjugation. Therefore, the secondary radical formed at C2 will be favored.

### Step 6: Attack of Bromine Radical
The bromine radical (Br•) will preferentially attack the more stable secondary radical (at C2). This leads to the formation of a brominated product.

### Step 7: Final Product Formation
After the bromine radical attacks the secondary radical, the hydrogen radical (H•) will then add to the remaining radical site, resulting in the formation of the final product.

### Step 8: Identify Product Z
The final product after the addition of HBr in the presence of H₂O₂ and light will be 2-bromobutane (CH₃-CHBr-CH₂-CH₃).

### Conclusion
Thus, the product Z in the sequence of reactions is **2-bromobutane**.

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