`BrCH_(2) - CH_(2) - CH = O and CH_(3) - CH_(2) - undersetunderset(Br)(|)C = O` are

Options

A. Functional isomers
B. Position isomers
C. Chain isomers
D. Metamers

Answer

To determine the relationship between the two given compounds, BrCH₂-CH₂-CHO and CH₃-CH₂-COBr, we will analyze their structures and functional groups step by step.

### Step 1: Identify the Functional Groups
- The first compound, BrCH₂-CH₂-CHO, has an aldehyde functional group (CHO) and a bromine atom (Br) attached to a carbon chain.
- The second compound, CH₃-CH₂-COBr, has an acid bromide functional group (COBr).

### Step 2: Compare the Molecular Formulas
- For BrCH₂-CH₂-CHO:
- The molecular formula can be derived as follows:
- 3 Carbon atoms (C)
- 5 Hydrogen atoms (H)
- 1 Bromine atom (Br)
- 1 Oxygen atom (O)
- Thus, the molecular formula is C₃H₅BrO.

- For CH₃-CH₂-COBr:
- The molecular formula can be derived as follows:
- 3 Carbon atoms (C)
- 5 Hydrogen atoms (H)
- 1 Bromine atom (Br)
- 1 Oxygen atom (O)
- Thus, the molecular formula is also C₃H₅BrO.

### Step 3: Determine the Type of Isomerism
- Since both compounds have the same molecular formula (C₃H₅BrO), we need to check if they have different functional groups.
- The first compound has an aldehyde functional group, while the second compound has an acid bromide functional group.

### Step 4: Classify the Isomers
- Since the two compounds have different functional groups (aldehyde vs. acid bromide) but the same molecular formula, they are classified as **functional isomers**.

### Conclusion
The two compounds, BrCH₂-CH₂-CHO and CH₃-CH₂-COBr, are **functional isomers** because they have the same molecular formula but different functional groups.

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