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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BC bot CD`. If `angleADB = theta, BC = p and CD = q`, then AB is equal to

A

`(p^(2)+q^(2)costheta)/(pcostheta+q"sin"theta)`

B

`(p^(2)+q^(2))/(p^(2)costheta+q^(2)"sin"theta)`

C

`((p^(2)+q^(2))"sin"theta)/((pcostheta+q"sin"theta)^(2))`

D

`((p^(2)+q^(2))"sin"theta)/(pcostheta+q"sin"theta)`

Text Solution

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The correct Answer is:
D
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