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If tan (alpha-beta)=(sin 2beta)(3-cos 2b...

If `tan (alpha-beta)=(sin 2beta)(3-cos 2beta)`, then

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If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta), then ( i )tan(alpha)=2tan(beta)( ii) (1)/(2)tan(alpha)=tan(beta)( (ii) 2tan(alpha)=3tan(beta)( iv) 3tan(alpha)=2tan(beta)

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta) then (a) tan alpha=2tan beta(b)tan beta=2tan alpha(c)2tan alpha=3tan beta(d)3tan alpha=2tan beta

If 2tan alpha=3tan beta, prove that tan(alpha-beta)=(sin2 beta)/(5-cos2 beta)

If 2tan alpha=3tan beta, prove that tan(alpha-beta)=(sin2 beta)/(5-cos2 beta)

If n tan alpha=(n+1)tan beta then show that tan(alpha-beta)=(sin2 beta)/(2n+1-cos2 beta)

If 2tan alpha=3tan beta, then tan (alpha-beta)=(sin2 beta)/(5-cos2 beta)(b)(cos2 beta)/(5-cos2 beta)(c)(sin2 beta)/(5+cos2 beta)(d) none of these

If tan beta=3tan alpha, prove that tan(alpha+beta)=(2sin2 beta)/(1+cos2 beta)

If 3tan alpha=4tan beta ,then prove that tan(alpha-beta)=(sin beta*cos beta)/(3+sin^(2)beta)=(tan beta)/(4tan^(2)beta+3)

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these

alpha and beta are acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta) then tan alpha cot beta=

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