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In a monthly test, the teacher decides that there will be three questions, one from each of Exercises 5, 6 and 7 of the text book. If there are 12 questions in Exercise 5, 18 in Exercise 6 and 9 in Exercise 7, in how many ways can the three questions be selected ?

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To solve the problem of selecting one question from each of the three exercises, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the number of questions in each exercise:** - Exercise 5 has 12 questions. - Exercise 6 has 18 questions. - Exercise 7 has 9 questions. 2. **Determine the selection process:** - We need to select one question from Exercise 5, one from Exercise 6, and one from Exercise 7. 3. **Calculate the number of ways to select questions:** - The number of ways to select one question from Exercise 5 is \( 12C1 \), which is simply 12. - The number of ways to select one question from Exercise 6 is \( 18C1 \), which is simply 18. - The number of ways to select one question from Exercise 7 is \( 9C1 \), which is simply 9. 4. **Multiply the number of choices together:** - The total number of ways to select the three questions is given by: \[ \text{Total ways} = (12C1) \times (18C1) \times (9C1) = 12 \times 18 \times 9 \] 5. **Perform the multiplication:** - First, calculate \( 12 \times 18 = 216 \). - Then, multiply \( 216 \times 9 = 1944 \). 6. **Final Answer:** - Therefore, the total number of ways to select the three questions is **1944**.
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