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If `A=[alphabetagammaalpha]`is such that `A^2-I`, then(A) `1+alpha^2+betagamma=0` (B) `1-alpha^2+betagamma=0` (C) `1-alpha^2-betagamma=0` (D) `1+alpha^2-betagamma=0`

A

`1+alpha^(2)+betagamma=0`

B

`1-alpha^(2)+betagamma=0`

C

`1-alpha^(2)-betagamma=0`

D

`1+alpha^(2)-betagamma=0`

Text Solution

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The correct Answer is:
C
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